SOLUTION: help please! a triangle has its vertices at (6,0), (5,3), and (-1,-4) find the equation of the line through the vertices parallel to the opposite side.

Question 683785: help please! a triangle has its vertices at (6,0), (5,3), and (-1,-4) find the equation of the line through the vertices parallel to the opposite side.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
(6,0), (5,3), and (-1,-4)
Let A (6,0), B(5,3), and C(-1,-4)be the vertices of the triangle
Let P,Q be the mid points of AB & AC respectively
PQ is parallel to BC
Determine co ordinates of P & Q by mid point formula
A (6,0), B(5,3),
Let P(x3,y3)

p=((11/2),(3/2))
Similarly find co ordinates of Q the mid point of AC
Q=(x4,y4)
A (6,0), C(-1,-4)

Q=((5/2),(-2))
The equation of PQ
use formula
p=((11/2),(3/2)), Q=((5/2),(-2))
equation of PQ ->

multiply equation by 4

14x-12y=59 is the equation of PQ

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