SOLUTION: FIND THE POINT ON THE POSITIVE y-AXIS THAT IS A DISTANCE 5 FROM THE POINT P(3,4).

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Question 64975: FIND THE POINT ON THE POSITIVE y-AXIS THAT IS A DISTANCE 5 FROM THE POINT P(3,4).
Answer by funmath(2873) About Me  (Show Source):
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FIND THE POINT ON THE POSITIVE y-AXIS THAT IS A DISTANCE 5 FROM THE POINT P(3,4).
d=sqrt%28%28x2-x1%29%5E2%2B%28y2-y1%29%5E2%29
d=5, (x1,y1)=(3,4) and (x2,y2)=(0,y)
5=sqrt%28%280-3%29%5E2%2B%28y-4%29%5E2%29
5=sqrt%289%2B%28y-4%29%5E2%29
%285%29%5E2=%28sqrt%289%2B%28y-4%29%5E2%29%29%5E2
25=9%2B%28y-4%29%5E2
25-9=9-9%2B%28y-4%29%5E2
16=%28y-4%29%5E2
%2B-sqrt%2816%29=sqrt%28y-4%29%5E2
+\-4=y-4
4+\-4=y-4+4
4+\-4=y
4+4=y or 4-4=y
8=y or 0=y
Since 0 is neither positive nor negative, don't use it.
The point is (0,8)
Happy Calculating!!!