You can
put this solution on YOUR website!THE DECIBEL LEVEL OF SOUND IS GIVEN BY D=10 LOG(I/10^-12), WHERE I IS THE SOUND INTENSITY MEASURED IN WATTS PER SQUARE METER FIND THE DECIBEL LEVEL OF A WHISPER AT AN INTENSITY OF 5.4 x 10^-10 WATTS PER SQUARE METER.
:
D =

:
Substitute 5.4(10^-10) for I in the above equation:
:
D =

:
Note that

= 10^2
:
So we have:
D = 10*Log(5.4*(10^2))
D = 10*Log(540)
D = 10*2.73239
D = 27.32 dbw