SOLUTION: The perimeter of a rectangle is 310 feet. The length is 25 feet more than the width. Find the width and the length of the rectangle and the corresponding area of the rectangle

Algebra ->  Points-lines-and-rays -> SOLUTION: The perimeter of a rectangle is 310 feet. The length is 25 feet more than the width. Find the width and the length of the rectangle and the corresponding area of the rectangle      Log On


   

Question 472513: The perimeter of a rectangle is 310 feet. The length is 25 feet more than the width. Find the width and the length of the rectangle and the corresponding area of the rectangle
Answer by monika_p(71) About Me  (Show Source):
You can put this solution on YOUR website!
a - lenght
b- widht
Given
P=310
a= b+25
perimeter formula of rectangle
P=2a+2b
substitute for P and a
310=2*(b+25)+2b
b=65 then a= 90
Now you can find area using formula A=a*b