SOLUTION: The side of a square is 4 cm longer than a side of an equilateral triangle. The perimeter of the square 24 cm longer than the perimeter of the triangle. Find the lengths of a side

Algebra ->  Algebra  -> Points-lines-and-rays -> SOLUTION: The side of a square is 4 cm longer than a side of an equilateral triangle. The perimeter of the square 24 cm longer than the perimeter of the triangle. Find the lengths of a side       Log On

Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   

Question 41991This question is from textbook
: The side of a square is 4 cm longer than a side of an equilateral triangle. The perimeter of the square 24 cm longer than the perimeter of the triangle. Find the lengths of a side of the square and the side of the triangle.This question is from textbook

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
THE REASON FOR ADDING THE 24 TO THE TRIANGLE IS BECAUSE IT IS 24 CM SHORT OF THE SQUARES PERIMETER THUS TO BALANCE THE EQUATION YOU MUST EITHER ADD THE 24 TO THE PERIMETER OF THE TRIANGLE OR SUBTRACT 24 FROM THE PERIMETER OF THE SQUARE SO THE TWO EQUATIONS ARE BALANCED.

THE 4 SIDES OF THE SQUARE ARE (X+4) AND THE 3 SIDES OF THE TRIANGLE ARE X.
THEN THE PERIMETER OF THE SQUARE IS 4(X+4) OR 4X+16 & THE PERIMETER OF THE
TRIANGLE 3X & THE SQUARE 4X+16=3X+24 OR 4X-3X=24-16 OR X=8
TRINGLE SIDES=8 & THE SQUARE SIDES ARE 8+4=12
PROOF 3*8=24 PERIMETER OF THE TRIANGLE & 4(8+4)=4*12=48 & 48-24=24 THE
DIFFERENCE IN THE TWO PERIMETERS.