SOLUTION: The area of a rectangle is 20 square feet. write the perimeter of this rectangle as a function of the length of one of its sides,x

Question 30628: The area of a rectangle is 20 square feet. write the perimeter of this rectangle as a function of the length of one of its sides,x
Answer by sdmmadam@yahoo.com(530) (Show Source): You can put this solution on YOUR website!
The area of a rectangle is 20 square feet. write the perimeter of this rectangle as a function of the length of one of its sides,x
The length of the rectangle is x ft
Let the width be y ft
Given that the area of the rectangle is 20 sq ft
This is (xy) = 20
Dividing by x,we get the width y given by
y = 20/x ft
The perimeter of the rectangle = 2(length+width)
=2(x+20/x)
=2(x^2+20)/x ft
Answer: The perimeter of the rectangle = [2(x^2+20)/x]
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