# SOLUTION: find the equation of the straight line which passes through the point (-2,6) and is:- (a) parallel to the line with equation x=3 (b) perpendicular to the line with equation y +2x

Algebra ->  Algebra  -> Points-lines-and-rays -> SOLUTION: find the equation of the straight line which passes through the point (-2,6) and is:- (a) parallel to the line with equation x=3 (b) perpendicular to the line with equation y +2x       Log On

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 Click here to see ALL problems on Points-lines-and-rays Question 280974: find the equation of the straight line which passes through the point (-2,6) and is:- (a) parallel to the line with equation x=3 (b) perpendicular to the line with equation y +2x = 0 (c) parallel to the line with equation y - 3x=4Answer by richwmiller(9135)   (Show Source): You can put this solution on YOUR website!First there are an infinite number of equations that fit the descriptions not just one, so it is wrong to ask for "the equation". a)x=3 forms a vertical line. and we want a line that is parallel. x=-2 b) perpendicular to y+2x=0 y=-2x slope is -2 we want a slope of 1/2 for it to be perpendicular. first we need to find b in the equation y=mx+b 6=-2*1/2+b 6=-1+b 7=b y=x/2+7 check 6=-2/2+7 6=6 ok c) -2,6 parallel to y - 3x=4 y=3x+4 slope is 3 6=3*-2+b 6=-6+b 12=b y=3x+12 check 6=-2*3+12 6=6 ok