SOLUTION: my question is, y=-3x-4 and line J is perpindicular to the equation, but also passes through point (1,1) what is the answer?

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Question 238342: my question is, y=-3x-4 and line J is perpindicular to the equation, but also passes through point (1,1) what is the answer?
Answer by josmiceli(6796) About Me  (Show Source):
You can put this solution on YOUR website!
If a line has slope = m, then
any line perpendicular to it will have
slope = -1%2Fm
y+=+-3x+-+4
m+=+-3
Perpendicular line J, m%5BJ%5D+=+-%281%2F%28-3%29%29
m%5BJ%5D+=+1%2F3
So far I know line J has the form
y+=+%281%2F3%29x+%2B+b. I know it goes through (1,1),
so I can just plug these values for x and y
back into the equation for J
1+=+%281%2F3%29%2A1+%2B+b
b+=+1+-+1%2F3
b+=+2%2F3
The equation for J is y+=+%281%2F3%29x+%2B+2%2F3
I'll plot the 2 lines to check my work
+graph%28+400%2C+500%2C+-5%2C+5%2C+-5%2C+5%2C+-3x+-+4%2C+%281%2F3%29x+%2B+2%2F3%29+