SOLUTION: Find the perimeter and area of a right triangle if the shortest side is 9cm and the longest side is 15cm.

Question 186758This question is from textbook A Survey of Mathematics with Application
: Find the perimeter and area of a right triangle if the shortest side is 9cm and the longest side is 15cm. This question is from textbook A Survey of Mathematics with Application

Found 2 solutions by uday1435, checkley77:
Answer by uday1435(57) (Show Source): You can put this solution on YOUR website!
The longest side is the hypotenuse. So by Pythagorean Theorem, 15^2 = 9^2 + x^2
where x is the unknown side
x^2 = 15^2 - 9^2 = 225 - 81 = 144
so x = sqrt(144) = 12 cms
The perimeter = sum of the length of all 3 sides = 12+15+9 = 36 cms
Area = 1/2 base x height = 1/2 x 12 x 9 = 54 sq cms

If you still require further clarifications please write to udayakumar.t.r@gmail.com
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
a^2+b^2=c^2
9^2+b^2=15^2
81+b^2=225
b^2=225-81
b^2=144
b=sqrt144
b=12
a*b+c=perimeter.
8+12+15=35 cm. is the perimeter.
Area=ab/2
8*12/2=96/2=48 cm^2 is the area.

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