# SOLUTION: I am supposed to write the slope-intercept form of an equation that passes through the given point and is perpendicular to the graph of each equation. (1,-3), y=1/2x+4

Algebra ->  Algebra  -> Points-lines-and-rays -> SOLUTION: I am supposed to write the slope-intercept form of an equation that passes through the given point and is perpendicular to the graph of each equation. (1,-3), y=1/2x+4      Log On

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 Question 175244This question is from textbook Algebra 1 : I am supposed to write the slope-intercept form of an equation that passes through the given point and is perpendicular to the graph of each equation. (1,-3), y=1/2x+4This question is from textbook Algebra 1 Found 2 solutions by solver91311, josmiceli:Answer by solver91311(16877)   (Show Source): You can put this solution on YOUR website!First thing is to remember that perpendicular lines have slopes that are negative reciprocals. That is to say that if has a slope and has a slope then is perpendicular to if and only if . The slope of your given line is already in slope-intercept form, so you can see that the slope of the given line is because is the coefficient on the term. That means that the slope of any line perpendicular to the given line must be . Knowing the slope and a point, you can use the point-slope form of a line to create the desired equation. The point slope form is: where is the slope and (,) are the coordinates of the given point. Just plug in the numbers and then solve the resulting equation for to put the equation into slope-intercept form. Answer by josmiceli(9671)   (Show Source): You can put this solution on YOUR website!When an equation has the form , is the slope of the line is the slope of this line You are asked to find a line that is perpendicular to this one. A line that is perpendicular to another line will have a slope that is , so in your case Also given is the point (1,-3) that the line must pass through The general form of the slope-intercept equation is: , so, filling in the given data: answer