SOLUTION: what is the equation of the line passing through (0,15) perpendicular to the graph of y=-3/4x+2/3??? thanks.

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Question 17281: what is the equation of the line passing through (0,15) perpendicular to the graph of y=-3/4x+2/3???
thanks.
Answer by rapaljer(4551) About Me  (Show Source):
You can put this solution on YOUR website!
This is going to be easier than most problems to find the equation of a line. First, you are given the equation of a line y+=+%28-3%2F4%29x%2B+2%2F3. The slope of this line is the coefficient of x, which is -3%2F4. The slope of ANY line parallel to this line is ALSO -3%2F4 (no extra charge for that one!!), and the slope of ANY line that is PERPENDICULAR to this line is the NEGATIVE RECIPROCAL of this slope, which would be 4%2F3.

Now, if the line passes through (0,15), then the y-intercept is 15. The final answer for this problem is in the form y=mx%2Bb, where b is the y-intercept, which is 15, and m is the slope which is 4%2F3.

Final answer: +y=%284%2F3%29x%2B+15

R^2 at SCC