SOLUTION: Write an equation of the line that passes through the point at (4,4) and is perpendicular to the line whose equation is 2x+y=7.

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Write an equation of the line that passes through the point at (4,4) and is perpendicular to the line whose equation is 2x+y=7.


since given line which contains point (,), we will find a line perpendicular to using what we know:
we can write in the slope-intercept form as
the slopes of the perpendicular lines are negative reciprocal; so the slope is negative reciprocal of the slope from the line, or
since , the slope of the unknown line must be;



we also know that line goes through (,), and we can find the equation by plugging in this info into the formula
Point-Slope Formula:
where m is the slope and (,) is the given point(,)
Plug in, and ,





Here is the graph:
and
From the graph you can see that red line contains point (,)

Solved by pluggable solver: Solve the System of Equations by Graphing

Let's look at the first equation Multiply both sides of the first equation by the LCD 2 Distribute --------- So our new system of equations is: In order to graph these equations, we need to solve for y for each equation. So let's solve for y on the first equation Start with the given equation Add to both sides Rearrange the equation Divide both sides by Break up the fraction Reduce Now lets graph (note: if you need help with graphing, check out this solver) Graph of So let's solve for y on the second equation Start with the given equation Subtract from both sides Rearrange the equation Divide both sides by Break up the fraction Reduce Now lets add the graph of to our first plot to get: Graph of (red) and (green) From the graph, we can see that the two lines intersect at the point (,) (note: you might have to adjust the window to see the intersection)