SOLUTION: the perimeter of a rectangle is 66m if the width were double and the length were increased by 22m, the perimeter would be 136 what is the length and width of the rectangle
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Question 150830: the perimeter of a rectangle is 66m if the width were double and the length were increased by 22m, the perimeter would be 136 what is the length and width of the rectangle
Answer by mangopeeler07(462) (Show Source): You can put this solution on YOUR website!
the perimeter of a rectangle is 66m if the width were double and the length were increased by 22m, the perimeter would be 136 what is the length and width of the rectangle
2w+2L=66
2(2w)+2(L+22)=136
Solve for 2w in the first equation
2w=66-2L
Plug that into the second equation
2(66-2L)+2(L+22)=136
Distribute
132-4L+2L+44=136
Combine like terms
176-2L=136
Subtract 176 from both sides
-2L=-40
Divide both sides by -2
L=20
2w=66-2L
2w=66-2(20)
2w=66-40
2w=26
w=13
Answer:
Length=20m
Width=13m
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