SOLUTION: The perimeter of a rectangle is 208 inches. The length exceeds the width by 32 inches. Find the length and the width.
The length is ?
(Type an integer or a decimal)
The width
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-> SOLUTION: The perimeter of a rectangle is 208 inches. The length exceeds the width by 32 inches. Find the length and the width.
The length is ?
(Type an integer or a decimal)
The width
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Question 138482: The perimeter of a rectangle is 208 inches. The length exceeds the width by 32 inches. Find the length and the width.
The length is ?
(Type an integer or a decimal)
The width is ?
(Type an integer or a decimal)
Help me please..Thank you so much in advance.
You can put this solution on YOUR website! The perimeter of a rectangle is 208 inches. The length exceeds the width by 32 inches. Find the length and the width.
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Let the width be "x" in. ; then the length will be "x+32" in.
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Formula:
Perimeter = 2(length + width)
208 = 2(x+32 + x)
104 = 2x+32
2x = 72
x = 36 in. (this is the width)
x+32 = 68 in. (this is the length)
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Cheers,
Stan H.
The length is ?
(Type an integer or a decimal)
The width is ?
(Type an integer or a decimal)
(