SOLUTION: The equation h= -16t^2+112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground. F

Question 125190: The equation h= -16t^2+112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground. Find the time it takes for the arrow to
reach a height of 180 ft.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
is your equation for height. Since you are given the height of 180 ft., just replace h with 180 and solve it like any other quadratic equation.

If you divide through by -4, the coefficients become a little more manageable:

You can use the quadratic formula if you don't want to scratch your head over the factorization of this one, but the factors come out to:

So, or

Therefore, the arrow will be 180ft above the ground 2.5 seconds after it is released on the way up, and again at 4.5 seconds on the way down.

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