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Find the constant m for which all three lines x - y = -m …eq. 1 , 2x + y = m - 1 …eq. 2, and x + 5y = 4m + 1 …eq. 3 intersect at one point.
Note: Can you please show your full solution? Thank you!
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You have these three starting equations
x - y = -m (1)
2x + y = m - 1 (2)
x + 5y = 4m + 1 (3)
Add equations (1) and (2). You will get
3x = -1; hence x = .
Next, from equation (1) express y = x + m = .
Now, substitute both these expressions x = and y = into equation (3). You will get
+ = 4m + 1. (4)
You just have one equation for one single unknown m in both sides. It is easy to solve.
So, multiply equation (4) by 3 (both sides) to run from denominator. You will get
-1 + 15m - 5 = 12m + 3
15m - 6 = 12m + 3
3m = 3 + 6 = 9
m = 9/3 = 3.
ANSWER. m = 3.
Solved.
Quite simple and reasonably short. Isn't it ?
The strategy was to construct equation for single unknown "m" and then solve it.
Also notice that as soon as you found "m", you can find x and y momentarily
x = (you just know it); y = = = 2 = .
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Ignore the post by @josgarithmetic, since his solution is INCORRECT.