y = mx + b is the slope-intercept form of a line



m is the slope (the amount of rise divided by the amount of run, also known as (change in y) / (change in x))

b is the y-intercept (where the line crosses the y-axis, i.e. the y value you get when x=0)



Parallel lines have equal slope.



Using the point-slope form, y-y0 = m(x-x0) with m=2, (x0,y0) = (5,-1): 

y - (-1) = 2(x - 5)   << point-slope form of the parallel line

y + 1 = 2x - 10  

  y = 2x - 11     << slope-intercept form of the parallel line





 

Answer by mccravyedwin(407)   (Show Source): You can put this solution on YOUR website!
 
Equations of parallel lines need differ only by their constant term(s).

y = 2x-7 has only the constant term -7.  Substitute any letter for the constant
term, say b.

y = 2x+b

Now all we need do is substitute the point (5,-1) in it

 -1 = 2(5)+b
 -1 = 10+b
-11 = b

Substitute 11 for b in

y = 2x+b and get

y = 2x-11     <--answer

Edwin
 

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