SOLUTION: The length of a rectangle exceeds its breath by 3cm.find the area of the rectangle and the length of the diagonal if the perimeter of the rectangle is 30cm

Question 1164094: The length of a rectangle exceeds its breath by 3cm.find the area of the rectangle and the length of the diagonal if the perimeter of the rectangle is 30cm
Found 2 solutions by Boreal, greenestamps:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
x and x+3 are the dimensions
perimeter is the sum of twice of each or 2x+2x+6 or 4x+6
that equals 30, so 4x=24 and x=6 cm
the dimensions are 6 cm x 9 cm and the area is 54 cm^2,
the diagonal is the hypotenuse of a right triangle with legs 6 and 9 cm
it is sqrt(6^2+9^2)=sqrt 117 cm

Answer by greenestamps(13203) (Show Source): You can put this solution on YOUR website!

The perimeter is 30, so the semi-perimeter (length plus width) is 15.

Since the length is 3 more than the width, simple mental arithmetic gives us 9 and 6 as the length and width.

The area is length times width; the length of the diagonal is the length of the hypotenuse of a right triangle with legs 6 and 9.

You can do the calculations....

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