SOLUTION: The ordinate of a point P is twice the abscissa. The point is equidistant from (-3,1) and (8,2). Find the coordinates of P.
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Question 1144213: The ordinate of a point P is twice the abscissa. The point is equidistant from (-3,1) and (8,2). Find the coordinates of P.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The ordinate of a point P is twice the abscissa. The point is equidistant from (-3,1) and (8,2). Find the coordinates of P.
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The ordinate of a point P is twice the abscissa.
---> y = 2x
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The point is equidistant from (-3,1) and (8,2)
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Find the perpendicular bisector of the line thru the 2 points.
P is the intersection of that line and y = 2x
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