SOLUTION: Find the equation of circle center at (1,3) and tangent to the line 5x-12y=8. please explain.

Question 1115770: Find the equation of circle center at (1,3) and tangent to the line 5x-12y=8. please explain.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the equation of circle center at (1,3) and tangent to the line 5x-12y=8.
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You can find the equation of the line perpendicular to the given line thru the point.
then find the distance from the point to the line, that's the radius.
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Then is the circle.
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Or, use
5x-12y-8 = 0
a = 5, b = -12, c = -8
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to find the distance.
is the point.

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