SOLUTION: I am trying to write an equation on the line parallel to y=8x-1 that contains (-6,2). How do I do it?
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Question 1099368: I am trying to write an equation on the line parallel to y=8x-1 that contains (-6,2). How do I do it?
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39614) (Show Source): You can put this solution on YOUR website!
, shows slope is 8, so any line parallel will also have slope of 8.
point must include (-6,2);
Line Equation Wanted:
Answer by greenestamps(13196) (Show Source): You can put this solution on YOUR website!
Every line parallel to the line with equation y=8x-1 will have an equation of the general form y = 8x+k, where k is some constant.
To find the particular line that is parallel to the given line and passes through a particular point, plug the x and y value of that point into the general form and solve for k:
The equation you are looking for is
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