SOLUTION: Given the circle x^2+y^2-4x+y=7 1 determine the equation of the tangent to the circle at the point where x=-1 2 determine the point of intersection of these two tangents

Question 1088892: Given the circle x^2+y^2-4x+y=7
1 determine the equation of the tangent to the circle at the point where x=-1
2 determine the point of intersection of these two tangents
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!

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The two lines are tangent at (-1,-2) and (-1,1).

Center of the circle, (2, -1/2).

One line will have slope, the negative reciprocal of points (2, -1/2) and (-1,-2) and will contain (-1,-2); and the other line will have slope, the negative reciprocal of points (2, -1/2) and (-1,1) and will contain point (-1,1).
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Find equation of each of these lines, and find their intersection.
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