SOLUTION: The perimeter of a triangle is 44 cm. One of its sides is 4 cm smaller than the other and twice as long as the third side. Find the sides of the triangle?

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Question 1064160: The perimeter of a triangle is 44 cm. One of its sides is 4 cm smaller than the other and twice as long as the third side. Find the sides of the triangle?
Found 2 solutions by Alan3354, MathTherapy:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
The perimeter of a triangle is 44 cm. One of its sides is 4 cm smaller than the other and twice as long as the third side. Find the sides of the triangle?
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If by "the other" you mean side 2
------
s = side 2
side 1 = s - 4
side 3 = (1/2)s
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s + s-4 + s/2 = 44
2s - 4 + s/2 = 44
4s - 8 + s = 88
5s = 96
s = 19.2
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--> 19.2, 15.2 & 9.6
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It's not a clearly stated problem.
Math problems should not be subject to interpretation.

Answer by MathTherapy(10556)   (Show Source): You can put this solution on YOUR website!

The perimeter of a triangle is 44 cm. One of its sides is 4 cm smaller than the other and twice as long as the third side. Find the sides of the triangle?
Let the other (2nd) side be S

Then 1st side = S - 4

Also, 1st side is twice 3rd side, or 3rd side is 

Since the sides sum to 44 cm, we get: 





4S + S - 4 = 96 ------- Multiplying by LCD, 2

5S = 96 + 4

5S = 100

S, or  

 

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