SOLUTION: what is the angle derived from the equation x=y in the positive direction of x axis

Question 1062271: what is the angle derived from the equation x=y in the positive direction of x axis

Found 2 solutions by Alan3354, MathTherapy:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
what is the angle derived from the equation x=y in the positive direction of x axis
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tan(angle) = y/x = 1
--> 45 degs or pi/4 radians
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Or,
y = x --> slope m = 1
m = tangent of the angle with the x-axis = 45 degs

Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!

what is the angle derived from the equation x=y in the positive direction of x axis

The line, x = y is a positive one in the 3rd and 1st quadrants, but the positive direction of the x axis is the 1st quadrant.
The "y" and "x" axes form a angle in all 4 quadrants, and the line x = y, bisects this angle, thereby forming an angle that is:
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