SOLUTION: I need help figuring out this question we have to find the equation- Contains to (-3,5) and is perpendicular to 2x+3y=7

Question 1049391: I need help figuring out this question we have to find the equation- Contains to (-3,5) and is perpendicular to 2x+3y=7
Found 2 solutions by Fombitz, rothauserc:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
First find the slope of your original line.

Perpendicular lines have slopes that are negative reciprocals,

So then use the point slope form with this slope and the point,

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Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
2x +3y = 7
:
3y = -2x + 7
:
1) y = -2x/3 + 7/3
:
The line perpendicular to line 1) has a slope = the negative reciprocal of line 1)'s slope
:
slope(m) of line 1) = -2/3
:
therefore the slope of the perpendicular line is -(-3/2) = (3/2)
:
so far we have
:
y = 3x/2 + b, where b is the y intercept
:
use the given point (-3, 5)
:
5 = 3(-3)/2 + b
:
5 = -9/2 + b
:
b = (10/2) + (9/2) = 9.5
:
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y = 3x/2 +9.5 is equivalent to
:
2y -3x = 19
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:

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