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Question 1041526: If the point (x,3) is equidistant from (3,-2) and (7,4), find the value of x.
Found 2 solutions by robertb, Alan3354:
Answer by robertb(5830)   (Show Source):
Answer by Alan3354(69443)  (Show Source):
You can put this solution on YOUR website! If the point (x,3) is equidistant from (3,-2) and (7,4), find the value of x.
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There's more than 1 way to do this.
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Label the points: A(3,-2), B(7,4)
Find the perpendicular bisector of AB. The point will be on the bisector.
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Using distance formula:
d^2 = (x-3)^2 + (3+2)^2 distance^2 from A
d^2 = (x-7)^2 + (3-4)^2 distance^2 from B
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(x-3)^2 + (3+2)^2 = (x-7)^2 + (3-4)^2
Solve for x
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