# SOLUTION: The length of a rectangular garden is 1 ft more than 2 times its width. If the perimeter of the garden is 44 ft, find both dimensions of the garden.

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 Click here to see ALL problems on Points-lines-and-rays Question 102904: The length of a rectangular garden is 1 ft more than 2 times its width. If the perimeter of the garden is 44 ft, find both dimensions of the garden. Answer by jayanthihemkos@yahoo.com(87)   (Show Source): You can put this solution on YOUR website!The length of a rectangular garden is 1 ft more than 2 times its width. If the perimeter of the garden is 44 ft, find both dimensions of the garden. Let the width of the garden w = x The length of the garden l = 2x+1 peimeter of a rectangle = 2(l+w) 2(l+w) = 44 2(x+2x+1) = 44 (x+2x+1) = 44/2 3x+1= 22 3x+1-1=22-1 3x = 21 3x/3= 21/3 x = 7ft l = x = 7 ft w = 2x+1 w = 2(7) +1 w = 15 ft length = 7 ft and width = 15 ft is the solution