SOLUTION: Two vertices of a triangle are (2, 4) and (-2, 3) and
the area is 2 square units, the locus of the third
vertex is?
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Question 1009436: Two vertices of a triangle are (2, 4) and (-2, 3) and
the area is 2 square units, the locus of the third
vertex is?
Answer by josgarithmetic(39613) (Show Source): You can put this solution on YOUR website!
Those two points could serve as segment for the base; understanding Distance Formula, and area formula of a triangle assumed, the length of that base for those two given points is . The altitude of the triangle would be therefore .
Consider two line equations.
The base is on and another line to contain the unknown triangle's vertex is some , and you do not yet know b.
You want the distance between the two lines to be . Putting this as an equation, .
Understand that these are two parallel lines, and once you find b, ANY point on the line of the then found & solved b, will contain an acceptable "third" vertex, because any of them will be the h distance from the chosen base segment.
--
(Strategy as as much work as shown, done on paper - not finished beyond how was described here.)
Note that .
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