Questions on Geometry: Points, lines, angles, perimeter answered by real tutors!

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Question 162629: Find the value of each variable and the measure of each labeled angle:
There are two lines that cross (like an X)
The top is: (y plus x)degrees
The left is: 2x degrees
The right is: (y-x) degrees
I don't know how i'm supposed to solve with two variables
: Find the value of each variable and the measure of each labeled angle:
There are two lines that cross (like an X)
The top is: (y plus x)degrees
The left is: 2x degrees
The right is: (y-x) degrees
I don't know how i'm supposed to solve with two variables

Answer by Fombitz(1799) About Me  (Show Source):
You can put this solution on YOUR website!
drawing( 400, 300, -10, 10, -10, 10,<BR>
line(-5,7,5,-7),<BR>
line(-5,-7,5,7),<BR>
locate(-0.5,2.5,y+x),<BR>
locate(1.5,0,y-x),<BR>
locate(-2.5,0,2x)
<BR>

  )
I think this is what you mean??
OK, when you look at the pairs of angles, you have two types of angles:linear pairs and vertical angles.
Linear pairs sum to 180 degrees.
Vertical angles are congruent (same measure).
In your diagram, the linear pairs are:
2x and y+x
y+x and y-x
The vertical angles are :
2x and y-x
So let's build equations using this information.
1.2x+(y+x)=180
1.3x+y=180
.
.
.
2.(y+x)+(y-x)=180
2.2y=180
2.y=90
.
.
.
3.2x=y-x
3.3x-y=0
.
.
.
Since eq. 2 solved for y, you can use either 1 or 3 to solve for x. You could also add eq. 1 and eq. 3,
3x+y+(3x-y)=180
6x=180
x=30
.
.
.
So the three angles, given clockwise, are 60 degrees(2x), 120 degrees(y+x), and 60 degrees(y-x).
drawing( 400, 300, -10, 10, -10, 10,<BR>
line(-5,7,5,-7),<BR>
line(-5,-7,5,7),<BR>
locate(-0.5,2.5,120),<BR>
locate(1.5,0,60),<BR>
locate(-2.5,0,60)
<BR>

  )