Tutors Answer Your Questions about Permutations (FREE)
Question 529830: Four cards are sequentially drawn from a shuffled deck of 52 cards without replacement. 26 of these cards are red, and the remaining 26 are blue. find the probability of getting a red card on the selection of the third card, given that the first 2 cards drawn have been red.
Click here to see answer by Edwin McCravy(8999)  |
Question 529831: At a party there are two types of appetizers: A and B. The probability that a person chooses A is 0.3 while the probability that the person chooses B is 0.4. The probability that the person chooses both is 0.25. What is the probability that a person does not choose any appetizer?
Click here to see answer by swincher4391(726)  |
Question 530164: For a party, a person sets up 6 card tables and pushes them together in a row. How many people can be seated at the arrangement? (Note: Only one person can sit on each side of a card table.)
Please show your work, thank you!
Allen~
Chicago, IL
Click here to see answer by josmiceli(9817)  |
Question 532611: Hello, can you help my figure of this question. If one person selects two vehicles at random, what is the probability that the person selects 2 SUV's. The totat number of suv's are 45, the total number of cars are 83 and the car and suv total is 128.
Click here to see answer by htmentor(807)  |
Question 533454: You have nine people. Each day these nine people must break up into 3 groups of three. How many days can they meet without the same three people meeting again in any group of three? Hope that was clear enough and help will be greatly appreciated.
-D
Click here to see answer by scott8148(6628)  |
Question 533998: Page Turner loves discrete mathematics. She has 7 "graph theory" books, 8 books about combinatorics, and 7 "set theory" books. How many ways can she place her discrete mathematics books on the same shelf in a row if:
a) there are no restrictions.
b) graph theory books are next to each other but the others could be anywhere on the shelf.
c) books are organized by their topic (same kinds are next to each other).
Click here to see answer by sudhanshu_kmr(1152)  |
Question 535615: Please help me to solve this question :
How many different numbers can be formed by taking one, two, three and four digits from the digits 1, 2, 7 and 8, if repetition are not allowed?
can I do it this way :
4P1 x 4P2 x 4P3 x 4P4
= 4 x 12 x 24 x 24
= 27648
Click here to see answer by richard1234(5390)  |
Question 535615: Please help me to solve this question :
How many different numbers can be formed by taking one, two, three and four digits from the digits 1, 2, 7 and 8, if repetition are not allowed?
can I do it this way :
4P1 x 4P2 x 4P3 x 4P4
= 4 x 12 x 24 x 24
= 27648
Click here to see answer by htmentor(807)  |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825
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