Tutors Answer Your Questions about Permutations (FREE)
Question 72454: Determine the constant term in the expansion of (2x-2/5x^2)^8.
I am doing this math independently. I have looked through my textbooks, but cannot find what a consant term is. I have expanded this by binomial expansion but there is not one constant term in the solution as all constants are differnt numbers with differnt x values.
Thank you
Kristen
Click here to see answer by Edwin McCravy(8909)   |
Question 72460: Determine the coefficent of the term containing a^5 in the expansion of
(a - 1/a)^5
I got 1 for the coefficent of a^5. However, I can not read my teachers writing and I think that the the question could be, "Determine the coefficent of the term containing a in the expansion of (a - 1/a)^5". If this is the case I am not sure of the coefficent since there are two a's and when you expand using binomial expansion, there are two possible terms that have a values (either multipy the a's together to get a or there is just an a in one of the terms).
Thank you,
Kristen
Click here to see answer by stanbon(57361) |
Question 72469: Hi, I am resubmitting this question, as it might be confusing.
Determine the constant term in the expansion of
I am doing this math independently. I have looked through my
textbooks, but cannot find what a consant term is. I have
expanded this by binomial expansion but there is not one constant
term in the solution as all constants are differnt numbers with
differnt x values.
Thank you
Kristen
Click here to see answer by psbhowmick(529)  |
Question 74205: I have the following problem:
Let P(n, k) denote the number of permutations of k objects selected from a set of n. We have the formula P (n,k) = n!/(n-k)!
Prove that for all integers n>or=2, P(n+1,2)-P(n, 2)=2P(n, 1).
I did some research on factorial identities and got a little further, but I'm not getting to the desired end result. I guess where I'm most stuck is the goal -- is 2P(n,1) equal to 2(n!/(n-1)!)? I've never seen the '2P' before. Thanks!
Click here to see answer by stanbon(57361) |
Question 77763: I get10X 5040 =50400 is this right?
In how many ways can a phone number be created if there are ten ways that the first three digits can be arranged and then each of the remaining four digits canbe any digit from 0-9 as long as no digit is repeated in the group of 4?
Click here to see answer by stanbon(57361) |
Question 80736: If the first three digits of someone's phone number (do not include area code) are 777, How many different phone numbers could they have?
Please don't just give me and answer. I would like to know how to work this problem.
I know that there 7digits in a phone numer, and the first three digits are taken then there are 4digits availiable.
is it P=n/(n-r)! where n=7 and r=4 I am not sure.
Click here to see answer by stanbon(57361) |
Question 85082: hey i need help with word probabilitiesfor example...
the letters a through z are written on pieces of paper and placed in a jar. Four of them are selected one after the other without replacing any of them.
and
how do you know how to do it.
Click here to see answer by stanbon(57361) |
Question 85123: Using the letters of the word YOUNG, tell how many different 5-letter combinations are possible if:
the first letter must be Y
the vowels and consonants alternate, beginning with a consonant (Y is a consonant here and Y does not have to be first
Click here to see answer by jim_thompson5910(28595) |
Question 85233: State and multi-state lotteries are common in the U.S. To win a typical lottery, you must match 6 numbers between 1 and 40. How many different combinations are possible? What does that say about the chances of winning the lottery?
Click here to see answer by stanbon(57361) |
Question 85232: A pizza shop offers the following toppings: 8 different vegetables, 5 different meats, and 4 different cheeses.
How many ways can 4 toppings be selected where:
a.All the toppings are vegetables
b.All the toppings are meat
c.There is only cheese on the pizza
d.There are 2 vegetables, 1 meat and 1 cheese
e.There are 3 meats and 1 cheese.
Click here to see answer by stanbon(57361) |
Question 85182: State and multi-state lotteries are common in the U.S. To win a typical lottery, you must match 6 numbers between 1 and 40. How many different combinations are possible? What does that say about the chances of winning the lottery?
Click here to see answer by scianci(186) |
Question 85180: I've decided that the mentor group should be made up of 3 girls and 3 boys. Of the students who have A's 9 of them are girls and 6 are boys. How many ways can I form a group of 3 boys and 3 girls?
Click here to see answer by scianci(186) |
Question 85484: A pizza shop offers the following toppings: 8 different vegetables, 5 different meats, and 4 different cheeses.
How many ways can 4 toppings be selected where:
a.All the toppings are vegetables
b.All the toppings are meat
c.There is only cheese on the pizza
d.There are 2 vegetables, 1 meat and 1 cheese
e.There are 3 meats and 1 cheese.
: A pizza shop offers the following toppings: 8 different vegetables, 5 different meats, and 4 different cheeses.
How many ways can 4 toppings be selected where:
a.All the toppings are vegetables
b.All the toppings are meat
c.There is only cheese on the pizza
d.There are 2 vegetables, 1 meat and 1 cheese
e.There are 3 meats and 1 cheese.
Click here to see answer by checkley75(3666) |
Question 85849: Please throughly explain how to solve this problem:
To win the Lotto in the state of Alabama, one must correctly select 6 numbers from a collection of 49 (1 through 49). This order in which the selection is made does not matter. How many different selections are possible?
Thanks
Click here to see answer by checkley75(3666) |
Question 85849: Please throughly explain how to solve this problem:
To win the Lotto in the state of Alabama, one must correctly select 6 numbers from a collection of 49 (1 through 49). This order in which the selection is made does not matter. How many different selections are possible?
Thanks
Click here to see answer by Edwin McCravy(8909) |
Question 85850: Please help me find a solution to this problem
Blue-Bunny Ice Cream, sells 31 flavors.
A.) How many 2-dip cones are possible if order of flavors is to be considered and no flavor is repeated?
B.) How many 2-dip cones are possible if order of flavors is to be considered and flavors CAN be repeated.
C.) How many 2-dip cones are possible if order is NOT considered and NO flavor is repeated?
Thanks
Click here to see answer by Edwin McCravy(8909) |
Question 86700: May you help me in solving this problem? I'm afraid I don't even know what formula to use. I can't even find this section in my text book. Thanks!
Use these figures for 1999 resident U.S. population by age to answer this question:
AGE ------POPULATION (In Thousands)
0-19 ------75,791
20-39 ----81,004
40-59 ------62,383
75-84 -----11,145
85 and older ----3,628
A.) Find the Probability that the resident is under the age of 20.
B.) Find the Probability that the resident is in the 20-39 or 60-74 age group.
Click here to see answer by Flake(45) |
|
Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780
|
