Tutors Answer Your Questions about Permutations (FREE)
Question 404316: If a multiple-choice test consists of 5 questions each with 4 possible answers of which only 1 is correct,
In how many ways can a student check off one answer to each question and get only the
answer to the first question right?
Click here to see answer by sudhanshu_kmr(1152)  |
Question 404758: Suppose you have a group of six men and three women; you want to line them up so that no two women are standing next to each other. In how many ways can this be done?
I know there has to be an easier way to figure this out than to just write M/F in combination until all of the combination's are exhausted (which is the method my classmates have done, and they have answers ranging from 12 to 30 ways) - we just have not gone over the actual formulas for this, and I can't figure it out from the textbook.
Click here to see answer by sudhanshu_kmr(1152)  |
Question 404520: In how many ways can we form three groups of people from 5 people, with each of the two groups consisting of 2 people, and the last group with only one person?
In how many ways can we form 4 groups of people from 11 people, where one group consists of 4 people, another group has 3 people, and each of the two remaining groups consisting of 2 people?
The order of the grouping doesn't matter.
Click here to see answer by sudhanshu_kmr(1152)  |
Question 405166: A typical social security number is 413-22-9802. If a social security number is chosen at random, what is the probability that all the digits will be the same? (social security number may begin with 0).
The answer is supposed to be 1/10^8
Thanks.
Click here to see answer by Edwin McCravy(8904)  |
Question 406031: Assume a telephone number consists of 8 digits, and the first and last digits cannot be 0.
(a) If repetitions are allowed, how many telephone numbers are possible if
(i) there is no restriction;
(ii) they are odd and start with 2?
(b) If repetitions are not allowed, how many telephone numbers are possible if
(i) there is no restriction;
(ii) they are divisible by 3 and the first digit is less than 5.
Click here to see answer by sudhanshu_kmr(1152)  |
Question 407243: a disc jockey wants to select four songs from a new cd of 12 songs. How many ways can the disc jockey choose four songs?
12 X 11 X 10 X 9 = 11880
He can choose any of 12 songs for his 1st song, then anyone of the remaining 11 for the 2nd, and so on.
Click here to see answer by unit(6) |
Question 407875: I can't seem to figure out this problem, can you help me?
find the number of outcomes of a space sample associated with this experiment:
picking 2 letters from the alphabet (no repetitions allowed; assume order is important)
I appreciate all your help!
Click here to see answer by jim_thompson5910(28548) |
Question 409323: A teacher has a class consisting of 8 BOYS and 4 GIRLS. How many groups of 5 can he make if:
-in every group there should be AT LEAST 1 girl?..
Thanks so much in advance. I'm not really sure how to solve for this... ^_^ God Bless
please send me the answer ASAP! :D it's our assignment thank you!
Click here to see answer by stanbon(57290) |
Question 409323: A teacher has a class consisting of 8 BOYS and 4 GIRLS. How many groups of 5 can he make if:
-in every group there should be AT LEAST 1 girl?..
Thanks so much in advance. I'm not really sure how to solve for this... ^_^ God Bless
please send me the answer ASAP! :D it's our assignment thank you!
Click here to see answer by sudhanshu_kmr(1152)  |
Question 409747: Suppose that you are playing a board game that has a spinner with 10 equal spaces. Suppose in a single game there was a total of 219 spins and 37 of them were the number 1.
What is the classical probability of spinning a 1?
In the long run, what would you expect the probability of a 1 to be?
What is the empirical probability of spinning a 1?
Click here to see answer by stanbon(57290) |
Question 412296: I was wondering if I could get an answer to see if I did this problem right?
How many different 6 letter words (real or imaginary) can be formed from the word MAYHEM?
6!/2!= 6*5*4*3*2/2*1
6*5*4*3=720
I hope I did this right.
Kim
Click here to see answer by stanbon(57290) |
Question 412296: I was wondering if I could get an answer to see if I did this problem right?
How many different 6 letter words (real or imaginary) can be formed from the word MAYHEM?
6!/2!= 6*5*4*3*2/2*1
6*5*4*3=720
I hope I did this right.
Kim
Click here to see answer by sudhanshu_kmr(1152)  |
Question 410237: Tom has 3 pairs of pants, 4 different colored dress shirts 3 sports jackets, 9 ties, and 1 pairs of dress shoes in his closet. How many different outfits can he select? Any combination of pants, shirt, jacket, tie and shoes is acceptable to him.
Click here to see answer by tallgirl84(3)  |
Question 410237: Tom has 3 pairs of pants, 4 different colored dress shirts 3 sports jackets, 9 ties, and 1 pairs of dress shoes in his closet. How many different outfits can he select? Any combination of pants, shirt, jacket, tie and shoes is acceptable to him.
Click here to see answer by sudhanshu_kmr(1152)  |
Question 405672: Suppose that in a senior college class of 500 students it is found that 210 smoke, 258 drink alcoholic beverages, 216 eat between meals, 122 smoke and drink alcoholic beverages, 97 smoke and eat between meals, and 52 engage in all 3 of these bad health practices. If a member of this senior class is selected at random, find the probability that the student:
eats between meals but does not drink alcoholic beverages nor smokes.
Click here to see answer by tallgirl84(3)  |
Question 412777: How many 7-digit numbers can be formed if the first digit cannot be 0 or 9 and if the last digit is greater than or equal to 4 and less than or equal to 5? Repeated digits are allowed.
I do not even remotley understand how to start this problem. Please explain how you got the answer so that I can learn this.
Click here to see answer by solver91311(16877)  |
Question 412869: Hi! I have a test tomorrow on this and I know how to do this type of problem, but don't know how to multiply them....
the problem is: 5C3 (5 choose 3) x 4C2 (4 choose 2)
Do I have to do both of them and multiply the results or is there a formula for this? Thanks in advance~
Click here to see answer by edjones(7569)  |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780
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