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Tutors Answer Your Questions about Permutations (FREE)
Question 2202: Congratulations! You have just won 25 video game tokens to use on these three challenging arcade gamse: Mighty Mediecal Monsters, Radical Racing Robots and Adventures Around the Amazon. All you have to do to collect your prize is answer this question: How many different ways are there to spend your 25 tokens on these three games provided that you play each game at least once?
Click here to see answer by khwang(438)  |
Question 2229: A teacher wants to write an ordered 5-question test from a pool of 8-questions. How many different forms forms of the test can the teacher write?
How many 5-number license plates can be made using the digits 1, 2, 3, 4, 5, 6, 7 if an odd digit must come first and repetitions are allowed? not allowed?
Suppose in Exercise 2 the license number must be odd. How would it be solved?
FHow would the number of pernutations of the letters of these words be found?
1. DEED 2. COMMITTE 3. CINCINNATI 4. SATELLITE 6. MASSACHUSETTS
A player in a word game has the letters E, E, B, D, G, G , G. In how many ways can these letters be arranged?
A. 210 B. 1260 C. 840 D. 420
What is the number of permutations of six numbers on a spinner?
In how mnay ways can the 10 awimmers on an aquatic ballet team be arranged in a cirurlar pattern?
Click here to see answer by longjonsilver(2297)  |
Question 4567: We are required to form different words with the help of letters of the word 'INTEGER'.
let m1 be the number of words in which 'I' and 'N' are never together and m2 be the number of words which begin with 'I 'and end with 'R',
then m1/m2 is given by ?
Click here to see answer by khwang(438)  |
Question 6558: the conjugate of
sqare_root(2)-square_root(3) is:
square_root(2)+square_root(3).
But can it be:
-sqare_root(2)-square_root(3)?
please note that even if they are not complex numbers ,
they are surds.
For surds conjugate of 2-square_root(3) is 2+square_root(3),
so why not -2-square_root(3)?
Click here to see answer by longjonsilver(2297)  |
Question 6863: I wasn't sure where to put this because my text is Inequalities, Permutations, and Probability. Can someone show me how to so this problem? How many different permutations can you make with the letters in the word
s e v e n t e e n ???? I am not sure how to set this problem up, Can someone please help me? I need to know how to do this before tomorrow(8-10-05)
Click here to see answer by longjonsilver(2297)  |
Question 6864: I am stuck on a question from my text book, on Inequalities, Permutations, and Probibility. Can someone help me? My question is....A teacher has a set of 12 problems to use on a math exam. The teacher makes different versions of the exam by putting 10 questions on each exam. How many different exams can the teacher make. I am not sure how to set up this problem. I keep multiplying 10 and 12 but I don't think that is right. Can someone help me. My paper is due tomorrow.
Click here to see answer by longjonsilver(2297)  |
Question 6874: I am having trouble with a question, and I think I know the answer and I just need someone to tell me if it is right. How many arrangements of the letters in the word o l i v e can you make if each arrangement must use three letter?
I think the answer is 5*4*3*2*1 is this answer right, Can someone please let me know. My paper is due tomorrow. Please?
Click here to see answer by Pieter(35)  |
Question 6886: I am having trouble with Inequalities, Permutations, and Probability. I was not sure what this question fit into, I hope that is alright. I am having trouble solving the inequality, -4y + 6<-14? I got it wrong on my homework, I had the answer y>2, Can someone please tell me what I did wrong?
Click here to see answer by glabow(165)  |
Question 6872: I am stuck on a question on Inequalities, Permutations, and Probibility. I think I know then answer but I am not sure. My question is Suppose you draw a card from a well-shuffled pack of playing cards. What is the probability that the card you draw will be an ace? I think the answer is 4:50, Is that the right answer? Please someone let me know.
Click here to see answer by glabow(165)  |
Question 7932: I wasn't sure where to put this because my text is Inequalities, Permutations, and Probability. Can someone show me how to so this problem? How many different permutations can you make with the letters a b c d e f g h i . I am not sure how to set this problem up, Can someone please help me? I need to know how to do this before tomorrow (8-22-05)
Click here to see answer by CharStar(110)  |
Question 10458: THE ARE 20 STUDENTS AND THEY NEED TO BE ALLOCATED INTO 3 CLASSROOMS.IN HOW MANY WAYS CAN THIS BE DONE
1.ASSUMING THAT THE STUDENTS ARE IDENTICAL
2.ASSUMING THAT THE STUDENTS ARE DISTINGUISHABLE
Click here to see answer by khwang(438)  |
Question 13331: Eight cards are selected with replacment from a standard pack of 52 playing cards, with 12 picture cards, 20 odd cards and 20 even cards. How many sequences of 8 are possible, that include 3 picture cards, 3 odd cards and 2 even cards,
Click here to see answer by khwang(438)  |
Question 13409: The probability of a basketball player's making a free throw successfully at any time in a game is 2/3. If the player attempts ten free throws in a game, what is the probablility that exactly six are made?
Click here to see answer by askmemath(368)  |
Question 14132: Let G be a group Under a binary operation "*" Having subgroups H and K such that HxK= G. I need some examples on this type of groups.
I have one example but I need more
G= group of all 2x2 matrices under addition.
A= group of all 2x2 matrices under addition having first element of first row as non-zero while all the other three are zero.
B= group of all 2x2 matrices under addition having second element of first row as non-zero while all the other three are zero.
c= group of all 2x2 matrices under addition having first element of second row as non-zero while all the other three are zero.
D= group of all 2x2 matrices under addition having second element of second row as non-zero while all the other three are zero.
then G = AxBxCxD that is G is direct product of A,B,C,D. Please give me such more examples.Thankyou.
Click here to see answer by khwang(438)  |
Question 15492: I posted this earlier, but never received a response...hopefully you can help me!
Suppose there are 10 items on a true-false test. The person taking the test does not read the questions; he just anserw each question randomly. What is the probability of his guessing all answers correctly?
Thanks..any help would be great.
Liz
Click here to see answer by venugopalramana(3286)  |
Question 20719: Five years ago, $10000 was invested at 6%/a compounded semi-annually. Today the investment rates have risen to 7%/a compounded annually. If the original investment and accumulated interest is rolled into the new investment conditions, how much will it be worth in five years.
Use A=P(1+i)^n
I know for 6% P=10000, i = 0.03 but I don't know what n =?
I know for 7% P=10000, i = 0.07 But I don't know what n =?
Click here to see answer by venugopalramana(3286)  |
Question 22720: State whether the situation involves a combination or premutation. then solve.
these where the directions from my book i need help with this problem and need to know how to tell what the difference between combination and permutation is and how do you tell which one is which. here is my problem
HOW MANY DIFFERENTNINE-PLAYER BATTING ORDERS CAN BE CHOSEN FROM A BASEBALL SQUAD OF 16?
HOW DO I DO THIS PROBLEME? PLEASE, PLEASE, PLEASE HELP ME
Click here to see answer by longjonsilver(2297)  |
Question 22918: I am learning counting in Algebra and Geometry and I am doing review for my test tmr. There's one question I can not do or understand in the review:
A cable contains 12 wires that are colour coded. There are 3 green, 3 red, 3 black, and 3 white wires. How many subsets of four wires can be seleted if there are no restrictions? Note: Order does matter! (Answer: 495)
Can you list out all the possible cases and show me how you calculate it. Thanks
Here's what I got (please tell me what I am doing wrong):
Case #1, all 4 wires are different
(3C1)^4 = 81 (Note 3C1 is 3 choose 1)
Case #2, 2 wires are the same colour, the other 2 is different (i.e. ggrb, rrgb etc)
4C3 * 4! / 2! = 48
Case #3, 2 pairs of the same colour (i.e. ggww, bbrr, etc.)
4C2 * 4! / 2! / 2! = 36
Case #4, 3 wires are same color and the other one is different (i.e. gggw, etc)
4C2 * 4! / 3! = 24
Click here to see answer by Earlsdon(4900)  |
Question 23354: A class of 14 students is made up of 6 girls and 8 boys
Determine the number of different groups of 5 that can be formed if there must be at most 1 boy in each group (there could be 0 or 1 boy in each group).
A. 23
B. 30
C. 120
D. 126
Click here to see answer by AnlytcPhil(958)  |
Question 23449: 1). Solve for r
7!/(7-r)! = 840
2). Expand (a-2)^5 using the binomal theoren.
(Is there a shorter way to expand this without multiplying (a-2) 5 times
and writing out a lot of numbers?)
a) a^5-8a^4+16a^3-24a^2+24a-32
b) a^5-10a^4+40a^3-80a^2+80a-32
Click here to see answer by venugopalramana(3286)  |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720
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