SOLUTION: 30 people from 10 families of 3 attend a meeting. If 5 people are asked to sit on 5 chairs on the stage and no two people come form the same family, how many arrangements are there

Question 965779: 30 people from 10 families of 3 attend a meeting. If 5 people are asked to sit on 5 chairs on the stage and no two people come form the same family, how many arrangements are there?
Answer by Edwin McCravy(20055) (Show Source): You can put this solution on YOUR website!

Choose a family for each chair in 10P5 = 10*9*8*7*6 ways.
Choose a family member to sit in each chairs in 3*3*3*3*3 = 3⁵ ways.

Answer 10*9*8*7*6*3⁵ = 7,348,320 ways.

Edwin

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