SOLUTION: in how many ways can 5 boys and 3 girls be arranged so that no two girls may sit together?
please help me out?i need this answer today.please please.................
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Question 96458: in how many ways can 5 boys and 3 girls be arranged so that no two girls may sit together?
please help me out?i need this answer today.please please.................
Answer by longjonsilver(2297) (Show Source): You can put this solution on YOUR website!
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These are all the 20 different versions of 5 Boys and 3 girls.
However, you can go one step further depending upon what your question implies...
in each version, the 5 boys can be arranged as b1...b2...b3...b4...b5 or other ways. These are a total of 5! = 5x4x3x2x1 = 120 ways
Also, the 3 girls can be sat 3! = 6 ways.
In addition, each version of the boys seating plan allows for all 6 of the girls seating plans so in total there, there are 120x6 = 720 versions.
so in total there are 20x720 = 14400 different permutations.
jon.
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