SOLUTION: We have 10 guest house and 7 guest.What is the number of permutations that we can arrange them ?
Algebra.Com
Question 956645: We have 10 guest house and 7 guest.What is the number of permutations that we can arrange them ?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
We have 10 guest house and 7 guest.What is the number of permutations that we can arrange them ?
-----------------
Ans: 10P7 = 10!/3! = 604800 ways
-----------
Cheers,
Stan H.
RELATED QUESTIONS
We are planning a reception for our daughter. The hall that we are renting charges a $50... (answered by ikleyn)
We are planning a reception for our daughter. The hall that we are renting charges a $90... (answered by ikleyn)
We are planning a reception for our daughter. The hall that we are renting charges a $90... (answered by ikleyn)
We are planning a reception for our daughter. The hall that we are renting charges a $55... (answered by ankor@dixie-net.com,MathLover1)
Sarah has 40 tacos and 5 guest. What's the least amount of tacos can each guest... (answered by Alan3354)
Sarah has 40 tacos and 5 guest. What's the least amount of tacos can each guest... (answered by ikleyn)
Write a full solution for the following question.
At at party you overhear another... (answered by Ahmath)
It is estimated that each guest at a party will eat 7/9 pounds of chocolates. How many... (answered by josmiceli)
To have a party at the sports club, you must pay $50 plus $5 per guest. Write an equation (answered by durga@tutor)