From a class of 6 male and 8 female students, a committee of 4 students is chosen. How many different committees contain more than 2 female students?
That's part of the answer, the number when the committee consiste of 1 male
and 3 females, but there is a second case! That is when the committee consists
of all females and no males.
Case 1. Committees with exactly 3 females and 1 male.
(8 females choose 3)*(6 males choose 1) = (8C3)(6C1) = (56)(6) = 336.
Case 2. Committees with exactly 4 females and no males.
(8 females choose 4)= (8C4)= 70.
Grand total: 336+70 = 406 ways.
Edwin