nC(r-1) + nC(r) ?=? (n+1)Cr ------------------------------------ (1) nCr =(2) nC(r-1) = = (3) (n+1)Cr = = --------------------------- We want to prove that expression(2) + expression(1) = expression(3) nC(r-1) + nCr = Substitute (n-r+1)(n-r)! for (n-r+1)! and r(r-1)! for r! LCD = r(r-1)!(n-r+1)(n-r)! replace r(r-1)! by r! and replace (n-r+1)(n-r) by (n-r+1)! (n+1)Cr Edwin