At bus stop, there are 11 people queueing, 7 adults and 4 chilcdren. Calculate
the number of arrangements of these 11 people such that FIRST and LAST people in
the queue are adults?
(There are 7 ADULTS.)
Choose the FIRST (1st) PERSON as any of those 7 ADULTS.
(There are now 6 ADULTS remaining.)
Choose the LAST (11th) PERSON as any of those 6 remaining ADULTS.
(There are now 9 PEOPLE remaining.)
Choose the 2nd PERSON as any of those 9 remaining PEOPLE.
(There are now 8 PEOPLE remaining.)
Choose the 3rd PERSON as any of those 8 remaining PEOPLE.
(There are now 7 PEOPLE remaining.)
Choose the 4th PERSON as any of those 7 remaining PEOPLE.
(There are now 6 PEOPLE remaining.)
Choose the 5th PERSON as any of those 6 remaining PEOPLE.
(There are now 5 PEOPLE remaining.)
Choose the 6th PERSON as any of those 5 remaining PEOPLE.
(There are now 4 PEOPLE remaining.)
Choose the 7th PERSON as any of those 4 remaining PEOPLE.
(There are now 3 PEOPLE remaining.)
Choose the 8th PERSON as any of those 3 remaining PEOPLE.
(There are now 2 PEOPLE remaining.)
Choose the 9th PERSON as either of those 2 remaining PEOPLE.
(There is now only 1 PERSON remaining.)
Choose the 10th PERSON as that 1 remaining PERSON.
7*6*9*8*7*6*5*4*3*2*1 = 7P2*9P9 = 15240960 ways.
Edwin