SOLUTION: find the number of permutations of the first 8 letters of the alphabet for each situation. taking all 8 letters at a time

Question 94372: find the number of permutations of the first 8 letters of the alphabet for each situation. taking all 8 letters at a time
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Since order does matter, we must use the permutation formula:

Start with the given formula

Plug in and

Subtract to get 0

Expand 8!

Expand 0! to get 1

Simplify

Now multiply 8*7*6*5*4*3*2*1 to get 40,320

So 8 choose 8 (where order does matter) yields 40,320 unique combinations

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
8P8 = 8! = 40,320
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Cheers,
Stan H.
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