SOLUTION: In selecting an ace;king;queen;and jack from an ordinary deck of 52 cards;how many ways may we choose if (a)they must be of different suits;(b)they may or may not be of different s

Question 940582: In selecting an ace;king;queen;and jack from an ordinary deck of 52 cards;how many ways may we choose if (a)they must be of different suits;(b)they may or may not be of different suits;(c)they must be of the same suit;(d)they must be in a particular suit?Please help me to solve this question.
Answer by Edwin McCravy(20054) (Show Source): You can put this solution on YOUR website!
In selecting an ace;king;queen;and jack from an ordinary deck of 52 cards;how many ways may we choose if
(a)they must be of different suits;

Choose the suit for the Ace 4 ways
Choose the suit for the King 3 ways
Choose the suit for the Queen 2 ways
Choose the suit for the Jack 1 way.

Answer 4*3*2*1 = 4! = 24 ways

(b)they may or may not be of different suits;

Choose the Ace 4 ways
Choose the King 4 ways
Choose the Queen 4 ways
Choose the Jack 4 ways

Answer: 4*4*4*4 = 4⁴ = 256 ways

(c)they must be of the same suit;

4 ways.  Just pick the suit.

(d)they must be in a particular suit?

1 way,  all in that particular suit.

Edwin

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