_____ A B C _____ D E F _____ G H I The Familiy can sit in 3!=6 ways on one of the 3 benches. That's 3*6 = 18 ways to seat the family. Suppose, for instance, that they sit in seats A,B, and C Next we seat the couple in 2! ways on D&E, E&F, G&H, or H&I So there are 2*4=8 ways to seat the couple. Then there are 4! = 24 ways to seat the random people. Answer: 18*8*24 = 3456 Edwin