7 seniors choose 3. That's C(7,3), or 7C3, which is 35 ways to choose the 3 seniors. For each of those 35 ways to choose the 3 seniors, there are 6 ways, 6C1, to choose the 1 junior. Answer = C(7,3)×C(6,1) = 35×6 = 210 ways. Edwin