SOLUTION: Show that:
n(2nCn) = (n+1)[2nC(n+1)]
Algebra.Com
Question 920297: Show that:
n(2nCn) = (n+1)[2nC(n+1)]
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
This follows straight from the definition of nCk:
Also,
RELATED QUESTIONS
Show that:
2[(2n-1)C(n-1)] =... (answered by jim_thompson5910)
Please show the following:
(1+2nC1 + 2nC2 +2nC3 +...+ 2nC(2n-1) + 2nC2n)^2 =... (answered by robertb)
Show that... (answered by jim_thompson5910)
Show that (n+1)! -3(n!) + (n-1)! =... (answered by Edwin McCravy)
Show that n! /r!(n-r)! + n!/(r-1)! (n-r+1)! = (n+1)!... (answered by math_helper)
Show that ((n+1) combination 1) - (n combination 1) =... (answered by greenestamps)
Show that (n + 1)^2 is a divisor of (n + 1)! + n! + (n -... (answered by tommyt3rd)
Show that |(-1)^(n+1) - (-1)^(n+2)| =... (answered by Alan3354)
Show that n <= 1 +sqrt(2)+sqrt(3)+...+sqrt(n) <=... (answered by ikleyn)