(a) For him to roll 2 6's, he will EITHER 1. choose a weighted die <--probability = 2/3 AND 2. roll a 6 the first time <--probability = 1/7 AND 3. roll a 6 the second time <--probability = 1/7 OR 1. choose a non-weighted die <--probability = 1/3 AND 2. roll a 6 the first time <--probability = 1/6 AND 3. roll a 6 the second time <--probability = 1/6 AND suggests multiplication and OR suggests addition:Approximately 0.023 --------- (b) P(weighted and (6 and 6) ) P(weighted die | rolled 2 6's) = ------------------------ P(6 and 6) The denominator is the result of part (a) = = = = about 0.595 Edwin