SOLUTION: The percentage of Americans who are vegetarians is 3.2%. Four people are randomly selected and are asked if they are vegetarians. Find the probability that at most one person said

Question 913000: The percentage of Americans who are vegetarians is 3.2%. Four people are randomly selected and are asked if they are vegetarians. Find the probability that at most one person said they are vegetarians. Hint: You must find the probability that zero people (x = 0) and one person (x = 1) said they are vegetarians.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Using
p and q are the probabilities of success and failure respectively.
In this case p = .032 and q = .968, n = 4

P(x ≤ 1) = P(0) + P(1) = (.968)^4 + 4C1 (.032)^1(.968)^2
Using TI
P(x ≤ 1) = binomcdf(4, .032, 1)

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