SOLUTION: How many different teams of 4 children can be chosen from a group of 19 girls and 17 boys if each team must have at least two boys in it? I think it would be nCr(36,4)/[nCr(17,2

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Question 907939: How many different teams of 4 children can be chosen from a group of 19 girls and 17 boys if each team must have at least two boys in it?
I think it would be nCr(36,4)/[nCr(17,2)*nCr(17,3)*nCr(17,4)]
So you need teams of 4(numerator)
and you need a minimum of two boys so exhaust all combinations(denominator)

Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!
First we'll find the number of teams of 4 from the 36 children without
restrictions of gender.  Then we'll subtract the number with no boys
and the number with just 1 boy.

1.  The number of teams with no restriction of gender.

That's 36C4 = 58905 teams with no restrictions of gender.

2.  The number of teams with no boys, which means 4 girls:

That's 19C4 = 3876 teams of all girls, no boys, which we must subtract.

3.  The number of teams with exactly 1 boy and 3 girls:

We can choose the 1 boy 17C1 = 17 ways.
Then we can choose the 3 girls 19C3 = 969 ways.
Thats 17(969) = 16473 ways, which we also must subtract.

Final answer = 58905-3876-16473 = 38556 teams with at least 2 boys.

Edwin

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