Let the seat numbers be: 1,2,3,4,5,6,7 Randy, Sandy, Candy and Dandy must sit in the 4 odd numbered seats. They can be placed in the 4 odd numbered seats in 4! ways. The other three children must be placed in the 3 even-numbered seats. They can be placed in the 3 even numbered seats in 3! ways. Answer 4!*3! = 24*6 = 144 ways. Edwin