SOLUTION: Thanks In Advance :)
A club wants to choose a committee of 4 people from its 12 members.
How many ways can the committee be chosen?
A.
48
B.
11,880
C.
19,9
Algebra.Com
Question 879608: Thanks In Advance :)
A club wants to choose a committee of 4 people from its 12 members.
How many ways can the committee be chosen?
A.
48
B.
11,880
C.
19,958,400
D.
495 (I think it's this one)
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
You are correct.
12 C 4 = (12!)/(4!*(12-4)!) = 495
We use a combination (instead of a permutation) since order doesn't matter.
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