SOLUTION: The number of possible sequences of all the hearts from a standard deck, given that the ace and king cannot be next to each other and that the 13 cards are dealt in a single row, i

Question 875907: The number of possible sequences of all the hearts from a standard deck, given that the ace and king cannot be next to each other and that the 13 cards are dealt in a single row, is __________________.
Found 2 solutions by ewatrrr, mckenzr:
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
8! - 7! = 35,280ways
7!(considering AK as 'one unit')
Answer by mckenzr(1) (Show Source): You can put this solution on YOUR website!
13! - ( 2!x 12 x 11!) = 5269017600 (this is the correct answer according to Foundations of Math 12 Workbook, Nelson).
It's all the possible arangements subtract the complement (how many arrangements can there be if the Ace and King ARE side by side).
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